Name of the Experiment: To
Determine The Resistance of a Galvanometer by Half-Deflection Method.
Theory: In the arrangement shown in Fig.
01, if the shunt resistance (S) is very small compared to the galvanometer
resistance RG, then the potential difference (V) between the ends of
the shunt resistance (S) remains nearly constant for all values of R1.
Thus when R1=0, then the galvanometer current Cg
is given by
Cg
=
= kd . . . . . . . . . . . . . . . (1)
Where d is the
deflection of the spot of light on the scale and k is the galvanometer
constant. If now a resistance R1 is introduced in the galvanometer
circuit such that the deflection reduces to
Where C’g is the new galvanometer
current.
Dividing (1) by (2), we get
Or,
+ R1 = 2
Or,
= R1 . . . . .. . . . . . . . . . . . . (3)
Hence by simply measuring
R1, RG can be found out. Fig. 1
Apparatus:
Zero point Galvanometer, Shunt Box S, Resistance R and R1,
Commutator K, Cell E, Connecting wires etc.
Procedure: Make connection
as shown in Fig. 1. Bring one sharp edge of the spot of light at the zero mark
of the scale.
1.
Insert a resistance (R) of the order of 1OOO ohms in the battery circuit. Make
Rt = o by putting all the plugs in the box. Beginning with the smallest value
(S = 0.1 ohm) of the shunt resistance S, go on increasing S until you obtain a
deflection of about lO cm on the scale. Note this deflection.
2.
keeping the resistance R constant, adjust the value of the resistance R1 until
the deflection is reduced to half of the former. Record this value of R1 which
is the value of the galvanometer resistance G.
3.
Stop the current in the circuit and examine if the same sharp edge of the spot
of light is still at zero of the scale. If not, adjust the scale to bring it to
zero. Make the value of R1 zero and keep R the same. Now reverse the current
with the commutator K. Repeat the whole operation to get another value of G
4. Keeping the value of the resistance R the
same, change the value of the shunt resistance S to obtain a different
deflection of round about lO cm and similarly determine the value of G.
5. Repeat the operation three times with
different value of R in the battery circuit and two values of S for each R.
Data
Collection:
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No. of Obs.
|
Direction
of Currents
|
Resistance R
Ω
|
Shunt resistance S
Ω
|
Resistance R1
Ω
|
Galvanometer Deflections
|
Resistance R1 =
RG
Ω
|
Mean
RG
Ω
|
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01
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Direct
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Reverse
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02
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Direct
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Reverse
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03
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Direct
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Reverse
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04
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Direct
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Reverse
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05
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Direct
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Reverse
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Calculation: Mean Galvanometer resistance
=
ohm’s
= ohm’s
From equation (3),
Galvanometer resistance RG = R1= ohm’s
Result:
The resistance of a Galvanometer is …………….. Ohm’s
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